Question

Thực hiện phép tính 

a) (2x^4-5x^2+x^3-3-3x):(x^2-3)       b) (x^5+x^3+x^2+1):(x^3+1)

c) (2x^3+5x^2-2x+3):(2x^2-x-1)        d) (8x-8x^3-10x^2+3x^4-5):(3x^2-2x+1)

Mik cần gấppp

Answer 1

a: \(=\dfrac{2x^4+x^3-5x^2-3x-3}{x^2-3}\)

\(=\dfrac{2x^4-6x^2+x^3-3x+x^2-3}{x^2-3}\)

\(=2x^2+x+1\)

b: \(=\dfrac{x^5+x^2+x^3+1}{x^3+1}=x^2+1\)

c: \(=\dfrac{2x^3-x^2-x+6x^2-3x-3+2x+6}{2x^2-x-1}\)

\(=x+3+\dfrac{2x+6}{2x^2-x-1}\)

d: \(=\dfrac{3x^4-8x^3-10x^2+8x-5}{3x^2-2x+1}\)

\(=\dfrac{3x^4-2x^3+x^2-6x^3+4x^2-2x-15x^2+10x-5}{3x^2-2x+1}\)

\(=x^2-2x-5\)