\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\ n_{HCl}=0,2\left(mol\right)\\ Zn+2HCl\rightarrow ZnCl_2+H_2\\ V\text{ì}:\dfrac{0,1}{1}=\dfrac{0,2}{2}\\ \Rightarrow Ph\text{ả}n.\text{ứn}g.h\text{ết}\\ n_{H_2}=n_{Zn}=0,1\left(mol\right)\\ V_1=V_{H_2\left(\text{đ}ktc\right)}=0,1.22,4=2,24\left(l\right)\)