\(\overline{M}_{khí}=15,5.2=31\left(g/mol\right)\)
Áp dụng sơ đồ đường chéo, ta có:
\(\dfrac{V_{O_2}}{V_{N_2}}=\dfrac{31-28}{32-1}=\dfrac{3}{1}\)
=> \(\left\{{}\begin{matrix}\%V_{O_2}=\dfrac{3}{1+3}.100\%=75\%\\\%V_{N_2}=100\%-75\%=25\%\end{matrix}\right.\)