ĐKXĐ: \(0\le x\le5\)
\(pt\Leftrightarrow4\sqrt{x+3}+16\sqrt{x}-8x=24-4\sqrt{5-x}\)
\(\Leftrightarrow\left(x+3-4\sqrt{x+3}+4\right)+\left(5-x-4\sqrt{5-x}+4\right)+\left(8x-16\sqrt{x}+8\right)=0\)
\(\Leftrightarrow\left(\sqrt{x-3}-2\right)^2+\left(\sqrt{5-x}-2\right)^2+8\left(\sqrt{x}-1\right)^2=0\)
\(\Rightarrow\left\{{}\begin{matrix}\sqrt{x-3}-2=0\\\sqrt{5-x}-2=0\\\sqrt{x}-1=0\end{matrix}\right.\) \(\Rightarrow x=1\)
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