ĐKXĐ: x>=3
\(\sqrt{x-3}=13\)
=>\(x-3=13^2=169\)
=>x=169+3=172(nhận)
\(\sqrt{x-3}\) = 13
x - 3 = 13^2
x - 3 = 169
x = 172
\(\sqrt{13+\sqrt{29+\sqrt{49}}}+x=\sqrt[3]{1000}-\sqrt{23+\sqrt{5893+\sqrt{1296}}}\)
\(\sqrt{13+\sqrt{29+\sqrt{49}}}+x=\sqrt[3]{1000}-\sqrt{23+\sqrt{5893+\sqrt{1296}}}\)
\(\sqrt{13+\sqrt{29+\sqrt{49}}}+x=\sqrt[3]{1000}-\sqrt{23+\sqrt{5893+\sqrt{1296}}}\)
Bài 13 : Cho A =\(\dfrac{\sqrt{x}+1}{\sqrt{x}-3}\). Tìm x thuộc Z để A có giá trị là một số nguyên
So sánh x;y biết rằng:
a) x= \(2\sqrt{7}\); y=\(3\sqrt{3}\)
b)x= \(6\sqrt{2}\); y= \(5\sqrt{3}\)
c) x= \(\sqrt{31}-\sqrt{13}\); y = 6- \(\sqrt{11}\)
So sánh x và y
1) x = \(2\sqrt{7}\);y = \(3\sqrt{3}\)
2) x = \(6\sqrt{2}\);y= \(5\sqrt{3}\)
3) x= \(\sqrt{31}\)- \(\sqrt{13}\); y = 6- \(\sqrt{11}\)
Tìm GTLN
M=\(\frac{3\sqrt{x}+2010}{4\sqrt{x}+1}\)
N=\(\frac{13+3+\left|x-1\right|}{2.\left|1-x\right|+5}\)
Tìm GTLN:
\(A=-\sqrt{x+\frac{5}{41}}+\frac{7}{12}\)
\(B=\frac{-5}{13}-\sqrt{x-\frac{2}{3}}\)
bài 1: tìm x, biết:
a)\(\sqrt{x}\)=7
b)\(\sqrt{x+1}\)=11
c)\(\sqrt{x-3}\)=13
d)\(\sqrt{3x+4}\)=5
e)\(\sqrt{3x+\frac{1}{2}}\)\(-\frac{3}{2}\)=0
Tìm x biết \(x^2-2\sqrt{13}x+13=0\)
