\(29-12 \sqrt{5}=(2\sqrt{5}-3)^{2}\)
\(6-2 \sqrt{5}=(\sqrt{5}+1)^{2}\)
Đs:1
\(6-2 \sqrt{5}=(\sqrt{5}-1)^{2}\)
trên gõ nhầm nhé
\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}=\sqrt{\sqrt{5}-\sqrt{3-\sqrt{\left(2\sqrt{5}-3\right)^2}}}\)
\(=\sqrt{\sqrt{5}-\sqrt{6-2\sqrt{5}}}=\sqrt{\sqrt{5}-\sqrt{\left(\sqrt{5}-1\right)^2}}\)
\(=\sqrt{1}=1\)