\(\sqrt{5x}\cdot\sqrt{45}-3x\) (ĐK: x ≥ 0)
\(=\sqrt{5x\cdot45}-3x\)
\(=\sqrt{225x}-3x\)
\(=15\sqrt{x}-3x\)
\(=3\sqrt{x}\left(5-\sqrt{x}\right)\)
#Toru
ĐKXĐ: x>=0
\(\sqrt{5x}\cdot\sqrt{45}-3x=\sqrt{225x}-3x=12x-3x=9x\)
\(\sqrt{5x}\cdot\sqrt{45}-3x\) (ĐK: x ≥ 0)
\(=\sqrt{5x\cdot45}-3x\)
\(=\sqrt{225x}-3x\)
\(=15\sqrt{x}-3x\)
\(=3\sqrt{x}\left(5-\sqrt{x}\right)\)
#Toru
ĐKXĐ: x>=0
\(\sqrt{5x}\cdot\sqrt{45}-3x=\sqrt{225x}-3x=12x-3x=9x\)
a)\(\sqrt{4-5x}=12\) tìm x
b)\(\sqrt{10+\sqrt{3x}}=2+\sqrt{6}\)
c)\(\sqrt{4x+20}-3\sqrt{5+x}+\dfrac{4}{3}\sqrt{9x+45}=6\)
b)\(\sqrt{4x-20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\sqrt{\dfrac{3x-2}{x+1}}=3\)
d) \(\dfrac{\sqrt{5x-4}}{\sqrt{x+2}}=2\)
Rút gọn biểu thức M = \(\dfrac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right)\sqrt{9-x^2}}:2\sqrt{1+\dfrac{2x}{3-x}}\)
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
Rút gọn biểu thức:\(\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right)\sqrt{9-x^2}}\)
Rut gọn: \(A=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right)\sqrt{x^2-6x+8}}\)
Cho A =\(\frac{x^3+2x^2+3x+x^2\sqrt{4-x^2}+6}{\sqrt{x+3}+3}:\frac{x^2\left(\sqrt{x+2}+\sqrt{2-x}\right)+3\sqrt{x+2}}{2\sqrt{x+3}-3\sqrt{x+2}-\sqrt{x^2+5x+6}}\)
Rút gọn a
Thu gọn rồi tính giá trị biểu thức:
\(B=\sqrt{\frac{x+5}{2}-\sqrt{5x}}\) tại \(x=5\sqrt{2}\)