\(\sqrt{24+16\sqrt{2}}-\sqrt{24-16\sqrt{2}}=\sqrt{8\left(3+2\sqrt{2}\right)}-\sqrt{8\left(3-2\sqrt{2}\right)}\)
\(=\sqrt{8}.\left[\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(\sqrt{2}-1\right)^2}\right]=\sqrt{8}.\left(\sqrt{2}+1-\sqrt{2}+1\right)=2\sqrt{8}=4\sqrt{2}\)
tính A=\(\sqrt{24+16\sqrt{2}}-\sqrt{24-16\sqrt{2}}\)
Rút gọn:
A=\(\sqrt{24+16\sqrt[]{2}}-\sqrt{24-16\sqrt[]{2}}\)
A=\(\sqrt{24+16\sqrt{2}}-\sqrt{24-16\sqrt{2}}\)
B=\(\sqrt{57-40\sqrt{2}}-\sqrt{40\sqrt{2+57}}\)
C=\(\sqrt{\sqrt{5}-\sqrt{3}-\sqrt{29}-12\sqrt{5}}\)
Mọi người làm nhanh hộ mình nhé
Giải pt và bpt sau:
a)\(\sqrt{x-2\sqrt{x-1}}\)=\(\sqrt{2}\)
b)\(\dfrac{4}{3}\sqrt{16\left(2-2x\right)^3}>24\)
\(\dfrac{2\sqrt{30}}{\sqrt{5}+\sqrt{6}+\sqrt{7}} \)
\(\sqrt{24}+6\sqrt{\dfrac{2}{3}+\dfrac{10}{\sqrt{6}-1}}\)
\(\dfrac{2\sqrt{15}+\sqrt{16}}{\sqrt{84}+\sqrt{6}}\)
\(2\sqrt{40\sqrt{2}}-2\sqrt{\sqrt{75}}-3\sqrt{5\sqrt{48}}\)
\(\dfrac{\left(2+\sqrt{3}\right)^2-1}{\left(\sqrt{3}+1\right)^2}:\dfrac{\left(3+\sqrt{5}\right)^2-4}{\left(\sqrt{5}+1\right)^2}\)
giúp em với ạ
THỰC HIỆN PHÉP TÍNH
1,\(\sqrt{1\dfrac{9}{16}}\)
2,\(\dfrac{\sqrt{12,5}}{0,5}\)
3,\(\sqrt{\dfrac{25}{64}}\)
4,\(\dfrac{\sqrt{230}}{\sqrt{2,3}}\)
5,\((\sqrt{\dfrac{2}{3}}+\sqrt{\dfrac{50}{3}}-\sqrt{24}).\sqrt{6}\)
Bài 1: Thực hiện phép tính:
a, \(\left(\sqrt{24}-\sqrt{48}-\sqrt{6}\right)\sqrt{6}+12\sqrt{2}\)
b, \(\left(\sqrt{\dfrac{1}{5}}-\sqrt{\dfrac{16}{5}}+\sqrt{5}\right):\sqrt{20}\)
c, \(\sqrt{21+3\sqrt{48}}-\sqrt{21-3\sqrt{48}}\)
Bài 2: Giải các phương trình sau:
a, \(\dfrac{1}{3}\sqrt{x-2}-\dfrac{2}{3}\sqrt{9x-18}+6\sqrt{\dfrac{x-2}{81}}=-4\)
b, \(\sqrt{9x^2+12x +4}=4x\)
c, \(\sqrt{x-2\sqrt{x-1}}=\sqrt{x-1}\)
GIÚP MIK VỚIIII
\(\sqrt{ x + 24} + \sqrt{ x - 16} = 10\)
