căn bậc hai của 16 bằng 4
vì: 4.4=42=16
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nhớ tích
căn bậc hai của 16 bằng 4
vì: 4.4=42=16
đúng 100%
nhớ tích
\(\sqrt{16}-\sqrt{9}+\sqrt{16+9}-\sqrt{\left(-2\right)^2}\)giup minh gap
Bài 1 : Tính hợp lý
\(\sqrt{0,36}:\sqrt{\frac{25}{16}}+\frac{1}{4}+\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-\sqrt{\frac{1}{16}}\)
Tính
1.\(2\sqrt{4}+4\sqrt{9}+6\sqrt{25}-4\sqrt{16}+\sqrt{0}\)
2. \(2\sqrt{0,09}-7\sqrt{2,25}+8\sqrt{\frac{16}{25}}-\sqrt{1}-0\sqrt{10,1}\)
5\(\sqrt{16}\)-4\(\sqrt{9}\)+\(\sqrt{25}\)-0,3\(\sqrt{400}\)
\(\left(\sqrt{1\frac{9}{16}}-\sqrt{\frac{9}{16}}\right)\)
E = \(5\sqrt{16}-4\sqrt{9}+\sqrt{25}-0,3\sqrt{400}\)
a,\(\sqrt{49-\sqrt{4+\sqrt{25}}}\)
b,\(\left(\sqrt{100-\sqrt{1}}\right):\sqrt{\left(-3\right)^2}\)
c,\(\sqrt{16+9-\sqrt{25-9}}\)
d,\(\sqrt{\left(-7\right)^2-\sqrt{1^{40}}.\sqrt{16}}\)
Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
\(\sqrt{0,49}+\sqrt{25-16}=\)
Tính \(\sqrt{1}-\sqrt{4}+\sqrt{9}-\sqrt{16}+\sqrt{25}-\sqrt{36}+.....-\sqrt{400}\)