Các câu hỏi tương tự
20 tháng 10 2021 lúc 10:26
Rút gọn
a)\(\sqrt{20}-15\sqrt{\dfrac{1}{5}}+\sqrt{\left(1-\sqrt{5}\right)^2}\)
b)\(\left(\dfrac{14}{\sqrt{14}}+\dfrac{\sqrt{12}+\sqrt{30}}{\sqrt{2}+\sqrt{5}}\right).\sqrt{5-\sqrt{21}}\)
lm giúp mik vs ạ
6 tháng 11 2021 lúc 13:57
Tính
\(\sqrt{25-\sqrt{21}}.\left(\dfrac{14}{\sqrt{14}}+\dfrac{\sqrt{30}+\sqrt{12}}{\sqrt{2}+\sqrt{3}}\right)\)
Biến đổi hđt sang dạng \(\sqrt{A^2}=\)/ A /
A.\(\sqrt{21+\sqrt{216}}-\sqrt{21-6\sqrt{6}}\)
B.\(\sqrt{9-4\sqrt{5}}+\sqrt{14+6\sqrt{5}}\)
C.\(\sqrt{88-30\sqrt{7}}-3\sqrt{7}\)
Rút gọn biểu thức :
a) A=\(\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\).
b)B=\(\sqrt[3]{20+14\sqrt{2}}+\sqrt[3]{20-14\sqrt{2}}\)
c) C=\(\sqrt[3]{9+4\sqrt{5}}+\sqrt[3]{9-4\sqrt{5}}.\)
Tính:
1) \(\sqrt{14-2\sqrt{33}}\)
2) \(\sqrt{12-2\sqrt{35}}\)
3) \(\sqrt{16-2\sqrt{55}}\)
4) \(\sqrt{14-6\sqrt{5}}\)
5) \(\sqrt{17-12\sqrt{2}}\)
6) \(\sqrt{27-12\sqrt{5}}\)
7) \(\sqrt{4+\sqrt{15}}\)
LÀM CHI TIẾT GIÚP MK NHÉ!
Rút gọn:
A=\(\sqrt{6-2\sqrt{5}}-\sqrt{6+2\sqrt{5}}\)
B=\(\sqrt{9+4\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)
C=\(\sqrt{14-6\sqrt{5}-\sqrt{14+6\sqrt{5}}}\)
\(\frac{\sqrt{12}-\sqrt{30}}{\sqrt{6}}.\frac{\sqrt{35}+\sqrt{14}}{\sqrt{7}}\)
giải nhanh giúp mình vs.
1) (\(5\sqrt{3}+2\sqrt{3}\)) (\(2\sqrt{3}-5\sqrt{2}\))
2) \(\sqrt{5+2\sqrt{ }6}-\sqrt{5-2\sqrt{ }6}\)
3)\(\sqrt{14}-6\sqrt{5}+\sqrt{14+6\sqrt{ }5}\)
\(\sqrt{14-6\sqrt{5}}+\sqrt{14+6\sqrt{5}}\)
ai làm nhanh giúp em vớia) Pfrac{2sqrt{8}-sqrt{12}}{sqrt{18}-sqrt{48}}-frac{sqrt{5}+sqrt{27}}{sqrt{30}+sqrt{162}}b) Qfrac{3+2sqrt{3}}{sqrt{3}}+frac{2+sqrt{2}}{sqrt{2}+1}-left(sqrt{2}+sqrt{3}right)c) Mleft(frac{2}{sqrt{3}-1}+frac{3}{sqrt{3}-2}+frac{15}{3-sqrt{3}}right).frac{1}{sqrt{3}+5}d) Nleft(frac{sqrt{14}-sqrt{7}}{1-sqrt{2}}+frac{sqrt{15}-sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{7}-sqrt{5}}
Đọc tiếp
ai làm nhanh giúp em với
a) P=\(\frac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\frac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
b) Q=\(\frac{3+2\sqrt{3}}{\sqrt{3}}+\frac{2+\sqrt{2}}{\sqrt{2}+1}-\left(\sqrt{2}+\sqrt{3}\right)\)
c) M=\(\left(\frac{2}{\sqrt{3}-1}+\frac{3}{\sqrt{3}-2}+\frac{15}{3-\sqrt{3}}\right).\frac{1}{\sqrt{3}+5}\)
d) N=\(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}+\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}-\sqrt{5}}\)