Question

sos

Answer 1

b: \(=\dfrac{18+3x}{2x\left(x+6\right)}=\dfrac{3}{2x}\)

d: \(=\dfrac{1-2x-6+3x-9}{\left(x+3\right)\left(x-3\right)}\cdot\dfrac{x+3}{x-14}=\dfrac{x-14}{x-14}\cdot\dfrac{1}{x-3}=\dfrac{1}{x-3}\)

Answer 2

b,\(=\dfrac{9}{x\left(x+6\right)}+\dfrac{3}{2\left(x+6\right)}=\dfrac{18+3x}{2x\left(x+6\right)}=\dfrac{3\left(x+6\right)}{2x\left(x+6\right)}=\dfrac{3}{2x}\)