so sánh:
a)\(\left(\frac{1}{80}\right)^7và\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5và\left(\frac{5}{243}\right)^3\)
giải chi tiết cho mk nha!!!
\(So\)\(sanh\):
a)\(\left(\frac{1}{80}\right)^7\)và\(\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5\)và \(\left(\frac{5}{243}\right)^3\)
So sánh hai phân số sau:
a)\(\frac{7}{15}và\frac{4}{9}\)
b)\(\frac{2001}{2002}và\frac{2000}{2001}\)
c)\(\left(\frac{1}{80}\right)^7và\left(\frac{1}{243}\right)^6\)
d)\(\left(\frac{3}{8}\right)^5và\left(\frac{5}{243}\right)^3\)
e) A=\(\frac{2011}{2012}+\frac{2012}{2013}\)Và B= \(\frac{2011+2012}{2012+2013}\)
f) \(C=\frac{20^{10}+1}{20^{10}-1}VàD=\frac{20^{10}-1}{20^{10}-3}\)
g) G =\(\frac{10^{100}+2}{10^{100}-1}\)Và H = \(\frac{10^8}{10^8-3}\)
h) E = \(\frac{98^{99}+1}{98^{89}+1}\) Và F =\(\frac{98^{98}+1}{98^{88}+1}\)
So sánh
a)\(\left(\frac{1}{80}\right)^7\)và \(\left(\frac{1}{243}\right)^6\)
b)\(\left(\frac{3}{8}\right)^5\)và \(\left(\frac{5}{243}\right)^3\)
c) \(\frac{10^{11}-1}{10^{12}-1}\)và \(\frac{10^{10}+1}{10^{11}+1}\)
1:So sánh:\(\left(\frac{1}{80}\right)^7\) và\(\left(\frac{1}{243}\right)^6\)
2:So sánh:\(\left(\frac{3}{8}\right)^5\)và\(\left(\frac{5}{243}\right)^3\)
làm nhanh giúp mình nhé!
So sánh
a) \(\left(\frac{1}{80}\right)^7\) với \(\left(\frac{1}{243}\right)^6\)
b) \(\left(\frac{3}{8}\right)^5\)với \(\left(\frac{5}{243}\right)^3\)
SO SÁNH
\(\left(\frac{1}{80}\right)^7va\left(\frac{1}{243}\right)^6\)
\(\left(\frac{3}{5}\right)^5va\left(\frac{5}{243}\right)^3\)
\(\frac{-22}{35}va\frac{-103}{177}\)
\(\frac{84}{-83}va\frac{-337}{331}\)
So sánh \(\left(\frac{1}{80}\right)^7\) với \(\left(\frac{1}{243}\right)^6\)
\(\left[x+\frac{1}{3}\right]+\left[x+\frac{1}{15}\right]+\left[x+\frac{1}{35}\right]+...+\left[x+\frac{1}{575}\right]\)
\(=11xx+\left[\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\right]\)