Question

so sánh \(\sqrt{3}\)và 5 - \(\sqrt{8}\)

Answer 1

$\sqrt{3}<\sqrt{4}=2$

$5-\sqrt{8}=5-2\sqrt{2}$ mà

$2\sqrt{2}=\sqrt{8}<\sqrt{9}=3$nên $5-2\sqrt{2}>5-3=2$

Vậy $\sqrt{3}<5-\sqrt{8}$

Answer 2

$\sqrt{3}<\sqrt{4}=2$

$5-\sqrt{8}=5-2\sqrt{2}$ mà

2√2=√8<√9=322=8<9=3nFe=nFe2On=a(mol)nên 5−2√2>5−3=25−22>5−3=256a+a(112+16n)=14,4(1)

Vậy √3<5−√8nSO2=0,1(mol)

Answer 3

\(\left(\sqrt{3}\right)^2=3\)

\(\left(5-\sqrt{8}\right)^2=33-10\sqrt{8}=3+30-10\sqrt{8}\)

mà \(0< 30-10\sqrt{8}\)

nên \(\sqrt{3}< 5-\sqrt{8}\)

Answer 4

$\sqrt{3}<\sqrt{4}=2$

$5-\sqrt{8}=5-2\sqrt{2}$ mà

$2\sqrt{2}=\sqrt{8}<\sqrt{9}=3$nên $5-2\sqrt{2}>5-3=2$

Vậy $\sqrt{3}<5-\sqrt{8}$