\(\dfrac{2016}{2019}< \dfrac{2016+1}{2019+1}=\dfrac{2017}{2020}\)
\(\Rightarrow\dfrac{2016}{2019}< \dfrac{2017}{2020}\)
Ta có:
\(\dfrac{2016}{2019}=1-\dfrac{3}{2019};\dfrac{2017}{2020}=1-\dfrac{3}{2020}\)
Do \(2019< 2020\Rightarrow\dfrac{3}{2019}>\dfrac{3}{2020}\)
\(\Rightarrow1-\dfrac{3}{2019}< 1-\dfrac{3}{2020}\)
Do đó:\(\dfrac{2016}{2019}< \dfrac{2017}{2020}\)