\(x=\dfrac{2}{-5}=\dfrac{-2\times13}{5\times13}=\dfrac{-26}{65}\)
\(y=\dfrac{-3}{13}=\dfrac{-3\times5}{13\times5}=-\dfrac{15}{65}\)
Do \(\dfrac{26}{65}>\dfrac{15}{65}\) nên \(-\dfrac{26}{65}< -\dfrac{15}{65}\)
Vậy \(x< y\)
\(\dfrac{2}{-5}=\dfrac{-2}{5}=\dfrac{-26}{65}\)
\(\dfrac{-3}{13}=\dfrac{-15}{65}\)
mà -26<-15
nên x<y