a, \(\dfrac{12}{17}=\dfrac{180}{255}\\ \dfrac{7}{15}=\dfrac{7.17}{17.15}=\dfrac{119}{255}\\ 180>119\\ \dfrac{12}{17}>\dfrac{7}{15}\\ B,\dfrac{1999}{2001}=\dfrac{21989}{22011}\\ \dfrac{12}{11}=\dfrac{24012}{22011}\\ 21989< 24012\\ \dfrac{1999}{2001}< \dfrac{12}{11}\)
Ta có : `12/24 = 1/2`
Mà : `12/17 > 12/24`
`=> 12/17 > 1/2`
`1/2 = 7/14`
Mà : `7/15 < 7/14`
`=> 7/15 < 1/2`
Vậy `12/17 > 7/15`
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Ta có : `1999/2001 < 1`
`12/11 > 1`
`=> 1999/2001 < 12/11`
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