a,-2( x-3 ) + 3( x-4 ) = 2 ( x+ 1 )
b,5( x+ 3 ) - 3 ( x- 7 ) = 4 ( x-7 )
c\(^{\left(x-1\right)^3=}\left(x-1\right)^2\)
d, 4x + 2 chia hết 2x -1
e \(x^2-4chiahetx+2\)
g 3x + 5 chia hết 2x -1
Nhờ mn giúp mik với ạ
Tìm GTNN
A= \(\left(x-3y\right)^2+\left(2x-1\right)^4\)
B= \(\left|x-2\right|+\left|3x-2y\right|-4\)
C= \(\dfrac{-4}{\left|x+1\right|\left|y-3\right|+2}\)
D=\(\left|x-5\right|+\left|x-1\right|+7\)
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
tìm x thuộc Z sao cho:
c, (4x+1) chia hết (2x+2)
e, \(\left(x^2-2x+3\right)⋮\left(x-1\right)\)
f,\(\left(3x-1\right)⋮\left(x-4\right)\)
g, \(\left(x^2+3x+9\right)⋮\left(x+3\right)\)
h, \(\left(2x^2-10x+5\right)⋮\left(x-5\right)\)
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)
Tìm số tự nhiên x , biết
\(2\cdot\left(x-1\right)^2=8\)
\(\left(2x+1\right)^3=125\)
\(\left(x-2\right)^5=243\)
\(5\left(x-4\right)^2-7=13\)
\(221-\left(3x+2\right)^3=96\)
Tìm x, biết:
\(a,\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(b,\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\)
\(c,\dfrac{x}{8}=\dfrac{9}{4}\)
\(d,\dfrac{x-3}{2}=\dfrac{18}{x-3}\)
\(e,4,5x-6,2x=6,12\)
\(h,11,4-\left(x-3,4\right)=-16,2\)
1. /x-5/=\(2^4\)-6
2.\(\frac{x-1}{3}+\frac{3x-5}{2}+\frac{2x}{3}+\frac{-5x+3}{9}=\frac{210}{420}\)
3.\(\left(4x-3\right)^4=\left(4^x-3\right)^2\)
4.\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{2}{x.\left(x+1\right)}=\frac{2015}{2017}\left(x\in N^{ }SAO\right)\)
\(\text{Tìm x, biết:}\)
\(a\)) \(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(b\)) \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(c\)) \(\left(x-\dfrac{3}{4}\right)\left(4+3x\right)=0\)
\(d\)) \(x-\dfrac{1}{3}x+\dfrac{1}{5}x=\dfrac{-26}{5}\)
\(e\)) \(50\text{%}x+\dfrac{2}{3}x=x-5\)
\(g\)) \(\dfrac{2}{3}\left(x+\dfrac{9}{5}\right)-\dfrac{3}{10}.\left(5x-\dfrac{1}{3}\right)=\dfrac{7}{15}\)