Question

rút gọn

A)(x-1)^3(x+2)(x^2-2x+4)+3x^2-2x

B)(2x-1)(4x^2+2x+1)-8(x^2+1)-5

Answer 1

a, (x-1)^3-(x+2)(x^2-2x+4)+3x^2-2x
= x^3-3x^2+3x-1-x^3-8+3x^2-2x
= x-9

b, 2.
a)(2x+y)(4x^2-2xy+y^2)-8x^3-y^3-16
= 8x^3+y^3-8x^3-y^3-16
= -16
=>Ko phụ thuộc vào biến 

Answer 2

a: \(A=\left(x^3-3x^2+3x-1\right)-\left(x^3+8\right)+3x^2-2x\)

\(=x^3-3x^2+3x-1-x^3-8+3x^2-2x\)

=x-9

b: \(B=8x^3-1-8x^2-8-5\)

\(=8x^3-8x^2-14\)