Question

rút gọn

\(1+4+4^2+4^3+.......+4^{99}+4^{100}\)

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Answer 1

`A=1+4+4^2+4^3+....+4^99+4^100`

`=>4A=4+4^2+4^3+4^4+...+4^100+4^101`

`=>4A-A=4^101-1`

`=>3A=4^101-1`

`=>A=(4^101-1)/3`

Answer 2

Ta có: \(A=1+4+4^2+...+4^{99}+4^{100}\)

\(\Leftrightarrow4\cdot A=4+4^2+4^3+...+4^{100}+4^{101}\)

\(\Leftrightarrow4\cdot A-A=4^{101}-1\)

hay \(A=\dfrac{4^{101}-1}{3}\)