\(N=\left(a-b\right)\cdot\sqrt{\dfrac{ab}{\left(a-b\right)^2}}\)
\(=\left(a-b\right)\cdot\dfrac{\sqrt{ab}}{\left|a-b\right|}\)
Vì a<b<0
nên a-b<0
=>|a-b|=-(a-b)
=>\(N=\left(a-b\right)\cdot\dfrac{\sqrt{ab}}{-\left(a-b\right)}=-\sqrt{ab}\)
\(N=\left(a-b\right).\sqrt{\dfrac{ab}{\left(a-b\right)^2}}=\left(a-b\right).\dfrac{\sqrt{ab}}{\left|a-b\right|}\\ =\left(a-b\right).\dfrac{\sqrt{ab}}{-\left(a-b\right)}=-\sqrt{ab}\left(a< b< 0\right)\)