b: \(\dfrac{\left(3x+2\right)^2-\left(x+2\right)^2}{x^3-x^2}\)
\(=\dfrac{\left(3x+2+x+2\right)\left(3x+2-x-2\right)}{x^2\left(x-1\right)}\)
\(=\dfrac{\left(4x+4\right)\cdot2x}{x^2\left(x-1\right)}\)
\(=\dfrac{8x\left(x+1\right)}{x^2\left(x-1\right)}=\dfrac{8}{x}\)