Question

Rút gọn phân thức x^3+64/2x^3-8x^2+32x

Answer 1

\(\dfrac{x^3+64}{2x^3-8x^2+32x}\\ =\dfrac{\left(x+4\right)\left(x^2-4x+16\right)}{2x\left(x^2-4x+16\right)}\\ =\dfrac{x+4}{2x}\)

Answer 2

\(\dfrac{x^3+64}{2x^3-8x^3+32x}\)

\(=\dfrac{\left(x+4\right)\left(x^2-4x+16\right)}{2x\left(x^2-4x+16\right)}\)

\(=\dfrac{x+4}{2x}\)