\(\frac{2}{\sqrt{4-3\sqrt[3]{5}+2\sqrt{5}-\sqrt[4]{125}}}.\)
rút gọn biểu thức
Rút gọn E=\(\frac{\sqrt{2}}{2}\)\(\sqrt{7+5\sqrt[4]{5}+3\sqrt[4]{25}+\sqrt[4]{125}}\)
rút gọn biểu thức :
\(\frac{2}{\sqrt{4-3\sqrt[4]{5}+2\sqrt[4]{25}-\sqrt[4]{125}}}\)
Rút gọn biểu thức
E=\(\frac{1}{\sqrt{4-3\sqrt[4]{5}+2\sqrt[4]{25}-\sqrt[4]{125}}}\)
Rút gọn biểu thức
I=(2\(\sqrt{3}\)-5\(\sqrt{27}\)+4\(\sqrt{12}\)):\(\sqrt{3}\)
K=\(\sqrt{125}\)-4\(\sqrt{45}\)+3\(\sqrt{20}\)-\(\sqrt{80}\)
L=2\(\sqrt{9}\)+\(\sqrt{25}\)-5\(\sqrt{4}\)
N=2\(\sqrt{32}\)-5\(\sqrt{27}\)-4\(\sqrt{8}\)+3\(\sqrt{75}\)
O=2\(\sqrt{3.5^2}\)-3\(\sqrt{3.2^2}\)+\(\sqrt{3.3^2}\)
Rút gọn bt
\(a,A=\frac{\left(5+2\sqrt{6}\right)\left(49-20\sqrt{6}\right)\left(\sqrt{5-2\sqrt{6}}\right)}{9\sqrt{3}-11\sqrt{2}}\)
\(b,C=\sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
\(c,\left(\sqrt{3}-1\right)\sqrt{6+2\sqrt{2}\sqrt{3-\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)
\(d,\sqrt[3]{3+\sqrt{9+\frac{125}{27}}}-\sqrt[3]{-3+\sqrt{9+\frac{125}{27}}}\)
rút gọn biểu thức
A=2\(\sqrt{27}\)+5\(\sqrt{12}\)-3\(\sqrt{48}\)
B=\(\sqrt{147}\)+\(\sqrt{75}\)-4\(\sqrt{27}\)
C=3\(\sqrt{2}\)(4-\(\sqrt{2}\))+3(1-2\(\sqrt{2}\))2
D=2\(\sqrt{5}\)-\(\sqrt{125}\)-\(\sqrt{80}\)+\(\sqrt{605}\)
RÚT GỌN
A.\(\sqrt{\frac{3\sqrt{3}-4}{2\sqrt{3}+1}+\sqrt{\frac{\sqrt{3}+4}{5-2\sqrt{3}}}}\)
B.\(\frac{\sqrt{4}+\sqrt{5}+\sqrt{4+5}}{\sqrt{4+\sqrt{11}}}\)
(1) rút gọn biểu thức:
a) A= \(3\sqrt{2}+5\sqrt{8}-2\sqrt{50}\)
b) B= \(\sqrt{7-4\sqrt{3}}+\sqrt{12+6\sqrt{3}}\)
c) C= \(\dfrac{1}{3+\sqrt{5}}+\dfrac{1}{3-\sqrt{5}}\)
d) D= \(\sqrt[3]{27}-\sqrt[3]{-8}-\sqrt[3]{125}\)
giúp mk vs ạ mai mk hc rồi