Giải:
a,\(\dfrac{2^5.3^2}{2^3.3}=2^2.3=12\)
b, \(\dfrac{5^3.6}{5.2^2}=\dfrac{5^3.2.3}{5.2^2}=\dfrac{5^2.3}{2}=37,5\)
c, \(\dfrac{8.5^2-8.4^2}{2^2.3^2}=\dfrac{8.\left(5^2-4^2\right)}{2^2.3^2}=\dfrac{8.9}{4.9}=2\)
d, \(\dfrac{7^4.2^2+7^4.3}{49.26}=\dfrac{7^4.\left(2^2+3\right)}{7^2.26}=\dfrac{7^4.7}{7^2.26}=\dfrac{343}{26}\)
Have a nice day!
a/ \(\dfrac{2^5\cdot3^2}{2^3\cdot3}=2^2\cdot3=12\)
b/ \(\dfrac{5^3\cdot6}{5\cdot2^2}=\dfrac{5^2\cdot6}{2^2}=\dfrac{150}{4}=37.5\)
c/ \(\dfrac{8\cdot5^2-8\cdot4^2}{2^2\cdot3^2}=\dfrac{200-2048}{36}=-\dfrac{1848}{36}\)
a)\(2^5.3^2\) /\(2^3.3\)
=\(2^3.2^2.3.3\)/\(2^3.3\)
=\(2^2.3\)/1
=12/1
b)\(5^3.6\)/5.\(2^2\)
=\(5^2.2.2.2\)/5.\(2^2\)
=5.2/1
=10/1
Giải:
a, \(\dfrac{2^5.3^2}{2^3.3}=2^2.3=12\)
b, \(\dfrac{5^3.6}{5.2^2}=\dfrac{5^3.2.3}{5.2^2}=\dfrac{5^2.3}{2}=37,5\)
c, \(\dfrac{8.5^2-8.4^2}{2^2.3^2}=\dfrac{8\left(5^2-4^2\right)}{4.9}=\dfrac{8.9}{4.9}=2\)
d, \(\dfrac{7^4.2^2+7^4.3}{49.26}=\dfrac{7^4.\left(2^2+3\right)}{7^2.26}=\dfrac{7^2.7}{26}=\dfrac{343}{26}\)
Have a nice day!