\(a,y\left(12y+3\right)+4\left(7-3y^2\right)=12y^2+3y+28-12y^2=3y+28\\ b,\left(x-2\right)^2-\left(3x+1\right)\left(x-3\right)=\left(x^2-4x+4\right)-\left(3x^2+x-9x-3\right)=x^2-4x+4-3x^2-x+9x+3=-2x^2+4x+7\)
a) y(12y + 3) + 4( 7- 3y2) = 12y2 + 3y + 28 - 12y2= 3y + 28
b)( x -2)2 - (3x + 1)(x - 3) = x2 - 4x +4 -(3x2 - 9x + x - 3)
=x2 - 4x +4 - 3x2 + 9x -x +3
= -2x2 + 4x +7