Question

Quy đồng x/(1 ^ 3 + 1); 1/1-x ; 1/(x ^ 2 + x + 1)

Answer 1

\(\dfrac{x}{x^3-1}=\dfrac{x}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(\dfrac{1}{1-x}=\dfrac{-1}{x-1}=\dfrac{-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(\dfrac{1}{x^2+x+1}=\dfrac{\left(x-1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)