Question

quy đồng mẫu các phân số sau: a, \(\frac{17}{320}và\frac{-9}{80}\)

b, \(\frac{-7}{10}và\frac{1}{33}\)

c, \(\frac{-5}{14},\frac{3}{20},\frac{9}{70}\)

d, \(\frac{10}{42},\frac{-3}{28},,\frac{-55}{132}\)

Answer 1

a) Ta có:  \(\frac{-9}{80}=\frac{\left(-9\right)x4}{80x4}=\frac{-36}{320}\) và \(\frac{17}{320}\)

b) Ta có:  \(\frac{-7}{10}=\frac{\left(-7\right)x33}{10x33}=\frac{-231}{330}\) và \(\frac{1}{33}=\frac{1x10}{33x10}=\frac{10}{330}\)

c) Ta có:

\(\frac{-5}{14}=\frac{\left(-5\right)x10}{14x10}=\frac{-50}{140}\)

\(\frac{3}{20}=\frac{3x7}{20x7}=\frac{21}{140}\)

\(\frac{9}{70}=\frac{9x2}{70x2}=\frac{18}{140}\)

d) Ta có: 

\(\frac{10}{42}=\frac{10x22}{42x22}=\frac{220}{924}\)

\(\frac{-3}{28}=\frac{\left(-3\right)x33}{28x33}=\frac{-99}{924}\)

\(\frac{-55}{132}=\frac{\left(-55\right)x7}{132x7}=\frac{-385}{924}\)