Question

Phân tích thành nhân tử:

\(xyz-\left(xy+yz+zx\right)+x+y+z\)

Answer 1

Sửa: \(xyz-\left(xy+yz+zx\right)+x+y+z-1\)

\(=-x\left(z-1\right)+xy\left(z-1\right)-y\left(z-1\right)+z-1\)

\(=\left(z-1\right)\left(xy-x-y+1\right)\)

\(=\left(z-1\right)\left[y\left(x-1\right)-\left(x-1\right)\right]\)

\(=\left(x-1\right)\left(y-1\right)\left(z-1\right)\)