\(x^4+2019x^2+2018x+2019\)
\(=x^4+x^2+1+\left(2018x^2+2018x+2018\right)\)
\(=x^4+x^2+1+2018\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+1\right)+2018\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+2019\right)\)
\(x^4+2019x^2+2018x+2019\)
\(=x^4+x^2+1+\left(2018x^2+2018x+2018\right)\)
\(=x^4+x^2+1+2018\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+1\right)+2018\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+2019\right)\)
phan tich da thuc thanh nhan tu
a,x4+2019x2+2018x+2019
b,(x+2)*(x+3)*(x+4)*(x+5)-24
Phân tích đa thức sau thanh nhân tử
x4+2019x2+2018x+2019
phan tich thanh nhan tu x2-3x+4=?
x^2-4+4xy-8y. Phan tich da thuc thanh nhan tu
Phan tich da thuc thanh nhan tu x^2(1-x^2)-4-4x^2
x^4+x^3-9x^2+10x-8 phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu
x^2(1-x^2)-4-4x^2
phan tich da thuc thanh nhan tu : x4+x2+1
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
phan tich da thuc thanh nhan tu
x^4+x^3+2x^2+x+1