Question

Phân tích thành nhân tử:

M=  x² - 5x + xy - 5y

N=  x² - 3x - 2xy + y² + 3y

K=  2xy + 3z + 6y +xz

Answer 1

\(M=x^2-5x+xy-5y=\left(x+y\right)\left(x-5\right)\)

\(N=x^2-3x-2xy+y^2+3y=\left(x-y\right)\left(x-y-3\right)\)\(K=2xy+3z+6y+xz=\left(x+3\right)\left(2y+z\right)\)

Answer 2

M= x²-5x+xy-5y= x(x-5)+y(x-5)=(x-5)(x+y)

N= x²-3x-2xy+y²+3y=(x-y)²-3(x-y)=(x-y)(x-y-3)

K= 2xy+3z+6y+xz=2y(x+3)+z(x+3)=(x+3)(2y+z)