\(2x^3-5x^2+8x-3\)
\(=2x^3-x^2-4x^2+2x+6x-3\)
\(=x^2\left(2x-1\right)-2x\left(2x-1\right)+3\left(2x-1\right)\)
\(=\left(2x-1\right)\left(x^2-2x+3\right)\)
2x3-5x2+8x-3=(2x3-x2)-4x2+8x-3=(2x3-x2)-4x2+2x+6x-3=(2x3-x2)-(4x2-2x)+(6x-3)
=x2(2x-1)-2x(2x-1)+3(2x-1)=(x2-2x+3)(2x-1)