Question

 

Phân tích đa thức thành  nhân tử

x³-5x²+8x-4

 

 

Answer 1

\(x^3-5x^2+8x-4\)

\(=x^3-x^2-4x^2+4x+4x-4\)

\(=\left(x^3-x^2\right)-\left(4x^2-4x\right)+\left(4x-4\right)\)

\(=x^2\left(x-1\right)-4x\left(x-1\right)+4\left(x-1\right)\)

\(=\left(x^2-4x+4\right)\left(x-1\right)\)

\(=\left(x^2-2.2x+2^2\right)\left(x-1\right)\)

\(=\left(x-2\right)^2\left(x-1\right)\)

Answer 2

=x³-x²-4x²+4x+4x-4

=x²(x-1)-4x(x-1)+4(x-1)

=(x-1)(x²-4x+4)

=(x-1)(x-2)²