Question

Phân tích đa thức thành nhân tử:

\(x^2-x-y^2-y\)                            \(a^3-a^2x-ay+xy\)

Answer 1

\(x^2-x-y^2-y\)

\(=\left(x^2-y^2\right)-\left(x+y\right)\)

\(=\left(x-y\right).\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right).\left(x-y-1\right)\)

\(a^3-a^2x-ay+xy\)

\(=\left(a^3-a^2x\right)-\left(ay-xy\right)\)

\(=a^2.\left(a-x\right)-y.\left(a-x\right)\)

\(=\left(a-x\right).\left(a^2-y\right)\)

Ủng hộ mk nha ^_-

Answer 2

xét x²-x-y²-y

=x^2-y^2-(x+y)

=(x+y)(x-y)+(x+y)

=(x+y)(x-y+1)

Câu tiep theo cau nhom hang tu thu nhat voi thu 3,thu 2 voi thu4