Question

Phân tích đa thức thành nhân tử:
a) 45x.(y-8)-27x.(8-y)
b) x²-49+4y²-4xy

Answer 1

a) \(45x\left(y-8\right)-27x\left(8-y\right)=45x\left(y-8\right)+27x\left(y-8\right)=\left(y-8\right)\left(45x+27x\right)=72x\left(y-8\right)\)

b) \(x^2-49+4y^2-4xy=\left(x-2y\right)^2-7^2=\left(x-2y-7\right)\left(x-2y+7\right)\)

Answer 2

a,=x(y-8)(45+27)=x(y-8)72

\(b,=\left(x-2y\right)^2-49=\left(x-2y+7\right)\left(x-2y-7\right)\)

tick mik nha

Answer 3

a: \(45x\left(y-8\right)-27x\left(8-y\right)\)

\(=45x\left(y-8\right)+27x\left(y-8\right)\)

\(=72x\left(y-8\right)\)

b: \(x^2-4xy+4y^2-49\)

\(=\left(x-2y\right)^2-49\)

\(=\left(x-2y-7\right)\left(x-2y+7\right)\)