Câu hỏi của tanqr

Question

Phân tích đa thức thành nhân tửa/ 3x2 – 24x + 48b/ 5x2 – 5c/ x2 + 2xy – 9 + y2

Nguyễn Hoàng Minh · Accepted Answer

$a,=3\left(x^2-8x+16\right)=3\left(x-4\right)^2\
b,=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)\
c,=\left(x+y\right)^2-9=\left(x+y+3\right)\left(x+y-3\right)$Câu trả lời: $a,=3\left(x^2-8x+16\right)=3\left(x-4\right)^2\
b,=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)\
c,=\left(x+y\right)^2-9=\left(x+y+3\right)\left(x+y-3\right)$

ILoveMath · Answer

a) $=3\left(x^2-8x+16\right)=3\left(x-4\right)^2$b) $=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)$c) $=\left(x+y\right)^2-9=\left(x+y-3\right)\left(x+y+3\right)$Câu trả lời: a) $=3\left(x^2-8x+16\right)=3\left(x-4\right)^2$b) $=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)$c) $=\left(x+y\right)^2-9=\left(x+y-3\right)\left(x+y+3\right)$

a) 5x – 15y	b) 5x²y² + 15x²y + 30xy²
c) x³ – 2x²y + xy² – 9x	d) x(x² – 1) + 3(x² – 1)
e) x² – 10x + 25	g) x² – 64
h) (x + y)² – (x² – y²)	i) 5x² + 5xy – x – y
k) x² – 25 + y² + 2xy	l) 2xy – x² – y² + 16
m) (x – 2)(x – 3) + (x – 2) - 1	n) 3(x – 1) + 5x( 1 – x)
p) 12y(2x – 5) + 6xy(5 – 2x)	q) ax – 2x – a² + 2a

a) a² – b² – 2a + 1	b) x² – 2x – 4y² – 4y
c) x² + 4x – y² + 4	d) x⁴ – 1
e) x⁴ + x³ + x² + x	g) a² + 2ab + b² – ac - bc

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