Question

Phân tích đa thức thành nhân tử:

\(8x^4y^4+12x^2y^4-16x^3y^4\)

Tìm x:

\(\left(x^3-1\right)-\left(x-1\right)\left(2-x^2\right)=0\)

Answer 1

\(=4x^2y^4\left(2x^2+3y^2-4x^2\right)\\ b,\left(x-1\right)\left(x^2+x+1\right)-\left(x-1\right)\left(2-x^2\right)=0\\ \left(x-1\right)\left(x^2+x+1-2+x^2\right)=0\\ \left(x-1\right)\left(2x^2+x-1\right)=0\\ \left[{}\begin{matrix}x-1=0\\2x^2+x-1=0\end{matrix}\right.=>x=1;x=-1;x=\dfrac{1}{2}\)