Question

Phân tích đa thức thành nhân tử

2xy-ax+x^2-2ay

Answer 1

2xy - ax + x²-2ay

= (2xy+x²) - (ax + 2ay)

= x(2y +x) - a (2y +x)

= (2y+x)(x-a)

Answer 2

\(2xy-ax+x^2-2ay\)

\(=\left(2xy+x^2\right)-\left(ax+2ay\right)\)

\(=x\left(2y+x\right)-a\left(x+2y\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

Answer 3

2xy - ax + x²-2ay

= (2xy+x²) - (ax + 2ay)

= x(2y +x) - a (2y +x)

= (2y+x)(x-a)

Answer 4

\(2xy-ax+x^2-2ay\)

\(=x\left(2y+x\right)-a\left(2y+x\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

Bỏ qua bước trung gian cũng được nha bạn 

Answer 5

Ta co

\(2xy-ax+x^2-2ay^{ }\)

\(=\left(2xy+x^2\right)-\left(ax+2ay\right)\)

\(=x\left(2y+x\right)-a\left(2y+x\right)\)

\(=\left(2y+x\right)\left(x-a\right)\)

Vay 2xy-ax+x^2-2ay= (2y+x)(x-a)