Question

Phân tích đa thức thành nhân tử

 

Answer 1

\(x^2-2xy+y^2-x+y\\ =\left(x^2-2xy+y^2\right)-\left(x-y\right)\\ =\left(x-y\right)^2-\left(x-y\right)\\ =\left(x-y\right)\left(x-y-1\right)\)

Answer 2

x2−2xy+y2−x+y=(x2−2xy+y2)−(x−y)=(x−y)2−(x−y)=(x−y)(x−y−1)

Answer 3

\(x^2-2xy+y^2-x+y\)

\(=\left(x^2-2xy+y^2\right)+\left(-x+y\right)\)

\(=\left(x^2-2xy+y^2\right)-\left(x-y\right)\)

\(=\left(x-y\right)^2-\left(x-y\right)\)

\(=\left(x-y\right)\left[\left(x-y\right)-1\right]\)

\(=\left(x-y\right)\left(x-y-1\right)\)