Question

phân tích đa thức thành nhân tử: xy²-4x+xyz+2xz

Answer 1

\(=x\left(y^2-4\right)+xz\left(y+2\right)\)

\(=x\left(y+2\right)\left(y-2\right)+x\left(y+2\right)z\)

\(=x\left(y+2\right)\left(y-2+z\right)\)

Answer 2

\(xy^2-4x+xyz+2xz\)

\(=x\left(y-2\right)\left(y+2\right)+zx\left(y+2\right)\)

\(=x\left(y+2\right)\left(y-2+z\right)\)