Question

phân tích đa thức thành nhân tử

    x2y2 + 2x2 + y2 + 2

     a2 - b2 +a - b 

Answer 1

\(x^2y^2+2x^2+y^2+2\)

\(=x^2\left(y^2+2\right)+\left(y^2+2\right)\)

\(=\left(x^2+1\right)\left(y^2+2\right)\)

\(a^2-b^2+a-b\)

\(=\left(a+b\right)\left(a-b\right)+\left(a-b\right)\)

\(=\left(a+b+1\right)\left(a-b\right)\)

Answer 2

\(a,x^2y^2+2x^2+y^2+2\)

\(=y^2\left(x^2+1\right)+2\left(x^2+1\right)\)

\(=\left(y^2+2\right)\left(x^2+1\right)\)

\(b,a^2-b^2+a-b\)

\(=\left(a+b\right)\left(a-b\right)+\left(a-b\right)\)

\(=\left(a-b\right)\left(a+b+1\right)\)

Answer 3

a.
=y²(x²+1)+2(x²+1)

=(x²+1)(y²+2)

b.
=(a-b)(a+b)+(a-b)
=(a-b)(a+b+1)

Answer 4

\(x^2y^2+2x^2+y^2+2\)

\(=\left(x^2y^2+2x^2\right)+\left(y^2+2\right)\)

\(=x^2\left(y^2+2\right)+\left(y^2+2\right)\)

\(=\left(y^2+2\right)\left(x^2+1\right)\)

\(a^2-b^2+a-b\)

\(=\left(a^2-b^2\right)+\left(a-b\right)\)

\(=\left(a-b\right)\left(a+b\right)+\left(a-b\right)\)

\(=\left(a-b\right)\left(a+b+1\right)\)