Question

phân tích đa thức thành nhân tử (thêm bớt) : x³-11x²+30x

 

Answer 1

x³ - 11x² + 30x = x(x² - 11x + 30) = x(x² - 6x - 5x + 30) = x[x(x - 6) - 5(x - 6)] = x(x - 5)(x - 6)

Answer 2

Trả lời:

x³ - 11x² + 30x

= x ( x² - 11x + 30 )

= x ( x² - 5x - 6x + 30 ) 

= x [ ( x² - 5x ) - ( 6x - 30 ) ] 

= x [ x ( x - 5 ) - 6 ( x - 5 ) ]

= x ( x - 6 ) ( x - 5 )

Answer 3

\(x^3-11x^2+30x\)

\(\rightarrow x.\left(x^2-11x+30\right)\)

\(\rightarrow x.\left(x^2-6x-5+30\right)\)

\(\rightarrow x.[x.\left(x-6\right)-5.\left(x-6\right)]\)

\(\rightarrow x.\left(x-5\right).x-6\)

Answer 4

\(x^3-11x^2+30x\)

\(=x\left(x^2-11x+30\right)\)

\(=x\left(x^2-6x-5x+30\right)\)

\(=x\left[x\left(x-6\right)-5\left(x-6\right)\right]\)

\(=x\left(x-6\right)\left(x-5\right)\)