Question

Phân tích đa thức thành nhân tử 
a) x² - 4xy + 4y²;     b) 9x²y² - 6xy + 1;    c) (x-1)³ - 1;                d) x³ - 3x² + 3x-1

Answer 1

\(a.=x^2-2x\cdot2y+\left(2y\right)^2=\left(x-2y\right)^2.\)

\(b.=\left(3xy\right)^2-2\cdot3xy\cdot1+1^2=\left(3xy-1\right)^2.\)

\(c.=x^3-3x^2+3x-1-1=x^3-3x^2+3x-2\)

\(=\left(x-2\right)\left(x^2-x+1\right).\)

\(d.x^3-3x^2+3x-1=\left(x-1\right)^3.\)

Answer 2

a: \(=\left(x-2y\right)^2\)

b: \(=\left(3xy-1\right)^2\)

c: \(=\left(x-1-1\right)\left(x^2+2x+1+x-1+1\right)\)

\(=\left(x-2\right)\left(x^2+3x+1\right)\)

d: \(=\left(x-1\right)^3\)