Question

Phân tích đa thức sau thành nhân tử 

x^3 + 2x^2y+xy^2-4x

Answer 1

x³ + 2x²y + xy² - 4x

= x( x² + 2xy + y² - 4 )

= x[ ( x + y )² - 2² ]

= x( x + y - 2 )( x + y + 2 )

Answer 2

\(x^3+2x^2y+xy^2-4x=\left(x^3+x^2y\right)+\left(x^2y+xy^2\right)-4x\)

\(=x^2\left(x+y\right)+xy\left(x+y\right)-4x\)

\(=x\left(x+y\right)^2-4x=x\left[\left(x+y\right)^2-4\right]=x\left(x+y+2\right)\left(x+y-2\right)\)

Answer 3

a) x^ 3 + 2x^ 2y + xy ^2 − 4x

= x (x^ 2 + 2xy + y^ 2 − 4)

= x [(x + y)^ 2 − 2 ^2]

= x (x + y + 2)(x + y − 2)