\(\left(3x-2y\right)^2-\left(2x-3y\right)^2\)
\(=\left(3x-2y+2x+3y\right)\left(3x-2y-2x+3y\right)\)
\(=\left(5x+y\right)\left(x+y\right)\)
(3x - 2y)2 - (2x - 3y)2 = (3x - 2y - 2x + 3y)(3x - 2y + 2x - 3y) = (x + y)(5x - 5y) = 5(x + y)(x - y)
(3x−2y)2−(2x−3y)2(3x−2y)2−(2x−3y)2
=(3x−2y+2x+3y)(3x−2y−2x+3y)=(3x−2y+2x+3y)(3x−2y−2x+3y)
=(5x+y)(x+y)