\(A=\sqrt{\left(2a\right)^2+\left(\dfrac{1}{a}\right)^2}+\sqrt{\left(2b\right)^2+\left(\dfrac{1}{b}\right)^2}+\sqrt{\left(2c\right)^2+\left(\dfrac{1}{c}\right)^2}\)
\(A\ge\sqrt{\left(2a+2b+2c\right)^2+\left(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right)^2}\)
\(A\ge\sqrt{4\left(a+b+c\right)^2+\left(\dfrac{9}{a+b+c}\right)^2}=\sqrt{4.2^2+\left(\dfrac{9}{2}\right)^2}=\dfrac{\sqrt{145}}{2}\)
\(A_{min}=\dfrac{\sqrt{145}}{2}\) khi \(a=b=c=\dfrac{2}{3}\)
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nhờ mọi người giúp vs ạ.
