\(v_{tb}=\dfrac{s+s'}{t+t'}=\dfrac{s}{\left(\dfrac{s}{2v}\right)+\left(\dfrac{s}{2v'}\right)}=\dfrac{s}{\left(\dfrac{2v's+2vs}{4v\cdot v'}\right)}=\dfrac{4v\cdot v'\cdot s}{2s\left(v'+v\right)}=\dfrac{2v'v}{v'+v}=\dfrac{2\cdot5\cdot3}{5+3}=3,75\cdot\dfrac{m}{s}\)