Question

mọi người ơi giúp e với ạ, e đang cần gấp ạ

Answer 1

\(\dfrac{7}{6}=1+\dfrac{1}{6};1,25=1+\dfrac{1}{4}\)

mà \(\dfrac{1}{6}< \dfrac{1}{4}\)

nên \(\dfrac{7}{6}< 1.25\)

mà \(1,25< 3,5< 5\sqrt{30}=\sqrt{750}\)

nên \(\dfrac{7}{6}< 1,25< 3,5< \sqrt{750}\)(1)

Ta có: \(\dfrac{1}{2}=1-\dfrac{1}{2};\dfrac{6}{7}=1-\dfrac{1}{7}\)

Ta có: 2<7

=>\(\dfrac{1}{2}>\dfrac{1}{7}\)

=>\(-\dfrac{1}{2}< -\dfrac{1}{7}\)

=>\(1-\dfrac{1}{2}< 1-\dfrac{1}{7}\)

=>\(\dfrac{1}{2}< \dfrac{6}{7}< 1< \dfrac{7}{6}\left(2\right)\)

\(-\dfrac{88}{101}>-1;-1>-1\dfrac{1}{2}\)

Do đó: \(-1\dfrac{1}{2}< -\dfrac{88}{101}< 0< \dfrac{1}{2}\left(3\right)\)

Từ (1),(2),(3) suy ra \(-1\dfrac{1}{2}< -\dfrac{88}{101}< \dfrac{1}{2}< \dfrac{6}{7}< \dfrac{7}{6}< 1,25< 3,5< \sqrt{750}\)