Gọi số mol Al, Zn là a,b
=> 27a + 65b = 11,9
\(n_{NO_2}=\dfrac{17,92}{22,4}=0,8\left(mol\right)\)
PTHH: Al + 6HNO3 --> Al(NO3)3 + 3NO2 + 3H2O
_____a---------------------------------->3a
Zn + 4HNO3 --> Zn(NO3)2 + 2NO2 + 2H2O
b------------------------------------>2b
=> 3a + 2b = \(\dfrac{17,92}{22,4}=0,8\)
=> a = 0,2 , b = 0,1
\(\left\{{}\begin{matrix}\%Al=\dfrac{0,2.27}{11,9}.100\%=45,378\%\\\%Zn=\dfrac{0,1.65}{11,9}.100\%=54,622\%\end{matrix}\right.\)
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