Câu 12: \(\overrightarrow{MP}=\overrightarrow{MA}+\overrightarrow{AD}+\overrightarrow{DP}\)
\(=-\frac12\cdot\overrightarrow{AB}+\overrightarrow{AD}+\frac12\cdot\overrightarrow{DC}\)
\(=-\frac12\cdot\overrightarrow{AB}+\overrightarrow{AD}+\frac12\left(\overrightarrow{AC}-\overrightarrow{AD}\right)=-\frac12\cdot\overrightarrow{AB}+\frac12\cdot\overrightarrow{AC}+\frac12\cdot\overrightarrow{AD}\)
\(=\frac12\left(-\overrightarrow{AB}+\overrightarrow{AC}+\overrightarrow{AD}\right)=\frac12\left(-\overrightarrow{b}+\overrightarrow{c}+\overrightarrow{d}\right)\)
=>Chọn D









