=>\(\dfrac{3\cdot3\left(x+5\right)}{12\left(x-5\right)\left(x+5\right)}-\dfrac{15}{2\left(x-5\right)\left(x+5\right)}=\dfrac{-14\left(x-5\right)}{12\left(x+5\right)\left(x-5\right)}\)
=>\(9\left(x+5\right)-90=-14x+70\)
=>9x-45=-14x+70
=>x=5(loại)
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